Q: Write C++ program to read two integer numbers then print "multiple" or "not" if one number is a multiple to another number. using do-while loop.
Sol//
#include <iostream>
using namespace std;
int main() {
int num1, num2;
cout << "Enter the first integer: ";
cin >> num1;
cout << "Enter the second integer: ";
cin >> num2;
// Check for division by zero first
if (num2 == 0) {
cout << "Error: Division by zero." << endl;
return 1; // Indicate error
}
int counter = 1;
bool isMultiple = false;
do {
if (counter * num2 == num1) {
isMultiple = true;
break;
}
counter++;
} while (counter * num2 <= num1);
if (isMultiple) {
cout << num1 << " is a multiple of " << num2 << endl;
} else {
cout << num1 << " is not a multiple of " << num2 << endl;
}
return 0;
}
Ex2: Write C++ program to read integer number and print the equivalent string. e.a: 0 ->zero 1-> one 2-> Two .
using do-while.
Sol//
#include <iostream>
#include <string>
using namespace std;
int main() {
int num;
string numberStrings[] = {"zero", "one", "two", "three", "four", "five",
"six", "seven", "eight", "nine"};
cout << "Enter an integer between 0 and 9: ";
cin >> num;
// Input validation (optional)
if (num < 0 || num > 9) {
cout << "Invalid input. Please enter a number between 0 and 9." << endl;
return 1; // Indicate error
}
int i = 0;
bool found = false;
do {
if (i == num) {
cout << numberStrings[i] << endl;
found = true;
break;
}
i++;
} while (i < 10);
if (!found) {
cout << "An unexpected error occurred." << endl; // Should never reach here with proper input validation
}
return 0;
}
Ex3: Write C++ program to read a score of student and print the estimation to refer it. e.a: 100 - 90 7 Exultant 89 - 80 ➔ Very good 79- 70 ➔ Good 69 - 60 7 Middle 59 - 50 ➔ Accept 49 - 0 ➔ Fail . using do-while.
Sol//
#include <iostream>
using namespace std;
int main() {
int score;
cout << "Enter the student's score (0-100): ";
cin >> score;
// Input validation (optional)
if (score < 0 || score > 100) {
cout << "Invalid score. Please enter a value between 0 and 100." << endl;
return 1; // Indicate error
}
string estimations[] = {"Exultant", "Very good", "Good", "Middle", "Accept", "Fail"};
int thresholds[] = {100, 90, 80, 70, 60, 50, 0}; // Assuming descending order
int i = 0;
bool found = false;
do {
if (score >= thresholds[i]) {
cout << "Estimation: " << estimations[i] << endl;
found = true;
break;
}
i++;
} while (i < 6 && !found);
if (!found) {
cout << "An unexpected error occurred." << endl; // Should never reach here with proper input validation
}
return 0;
}
Ex4: Write C++ program to read an integer number and check if it is positive or negative, even or odd, and write a suitable messages in each case. using do-while loop.
Sol//
#include <iostream>
using namespace std;
int main() {
int num;
cout << "Enter an integer: ";
cin >> num;
bool isPositive = true; // Assume positive initially (for do-while loop)
bool isEven = true; // Assume even initially (for do-while loop)
int i = 1;
do {
if (num < 0) {
isPositive = false;
break;
}
i++;
} while (i <= abs(num)); // Check for positive/negative
i = 1; // Reset counter for even/odd check
do {
if (i % 2 != 0) {
isEven = false;
break;
}
i += 2; // Only check even numbers for efficiency
} while (i <= abs(num)); // Check for even/odd
cout << num << " is ";
if (isPositive) {
cout << "positive";
} else {
cout << "negative";
}
cout << " and ";
if (isEven) {
cout << "even." << endl;
} else {
cout << "odd." << endl;
}
return 0;
}
Ex5: Write C++ program to reads a character and print if it is digit (0 .. 9), capital letter (A,B, ... ,Z), small letter (a, b, ... ,z), special character ( +, !, @, #, ~ {, >, ... ). using do-while.
Sol//
#include <iostream>
#include <cctype> // For character classification functions
using namespace std;
int main() {
char ch;
cout << "Enter a character: ";
cin >> ch;
bool isFound = false;
do {
if (isdigit(ch)) {
cout << ch << " is a digit." << endl;
isFound = true;
break;
} else if (isupper(ch)) {
cout << ch << " is an uppercase letter." << endl;
isFound = true;
break;
} else if (islower(ch)) {
cout << ch << " is a lowercase letter." << endl;
isFound = true;
break;
}
// No need to explicitly check for special characters here
} while (!isFound);
return 0;
}
Ex6- Write C++ program to find the following series: using do-while loop.
Sol//
#include <iostream>
#include <cmath> // for pow function
using namespace std;
int main() {
int n = 10; // Number of terms (change to 10 for the specific series)
double sum = 0;
int i = 1;
do {
sum += pow(2, i); // Calculate 2 raised to the power of i and add to the sum
i++;
} while (i <= n);
cout << "The sum of the series 2^1 + 2^2 + ... + 2^" << n << " is: " << sum << endl;
return 0;
}
Ex7- Write C++ program to find the following series: using do-while loop.
Sol//
#include <iostream>
using namespace std;
int main() {
double z = 0.0;
int sign = 1; // Start with positive sign
int denominator = 3; // Initialize denominator
do {
z += sign * (4.0 / denominator);
sign *= -1; // Alternate signs
denominator += 2; // Increment denominator by 2 for next odd number
} while (denominator <= 13); // Loop until denominator reaches 13
cout << "The sum of the series z = 4 - 4/3 + 4/5 - 4/7 + ... + 4/13 is: " << z << endl;
return 0;
}
Ex8: Write C++ program to inverse an integer number. For example: 7 65432 ➔ 234567 .using do-while loop?
Sol//
#include <iostream>
#include <limits> // for numeric_limits
using namespace std;
int main() {
long long int num; // Use long long to handle larger numbers
cout << "Enter an integer: ";
cin >> num;
// Check for negative input and handle overflow
if (num < 0) {
cout << "Error: Negative input is not allowed." << endl;
return 1; // Indicate error
} else if (num > numeric_limits<long long int>::max() / 10) {
cout << "Error: Number too large for inversion." << endl;
return 1; // Indicate error
}
long long int reversed = 0;
int digit;
do {
digit = num % 10;
reversed = reversed * 10 + digit;
num /= 10;
} while (num != 0);
cout << "The reversed number is: " << reversed << endl;
return 0;
}
Ex9: Write C++ program that utilize looping and the escape sequence \t to print the following table of value:
N , 1 0 * N ,100 * N ,1000 * N
1 10 100 1000
2 20 200 2000
3 30 300 3000
4 40 400 4000
Hint\t to print six spaces. using do-while loop.
Sol//
#include <iostream>
using namespace std;
int main() {
int N;
int i = 1; // Initialize loop counter
cout << "Enter a value for N: ";
cin >> N;
cout << "N\t10 * N\t100 * N\t1000 * N\n"; // Header row with labels
// Loop do-while (executes at least once)
do {
cout << i << "\t" << 10 * i << "\t" << 100 * i << "\t" << 1000 * i << endl;
i++; // Increment loop counter
} while (i <= 4);
return 0;
}
Ex10 : Write C++ program to find e from the following series: e = 1 + (1 /1 !) + (1 /2!) + (1 /3!) + ... + (1 /n!) . using do-while loop.
Sol//
#include <iostream>
#include <cmath> // for std::factorial
using namespace std;
int main() {
int n;
double e = 1.0; // Initialize with 1
cout << "Enter the number of terms (higher n for better accuracy): ";
cin >> n;
// Input validation (optional)
if (n <= 0) {
cout << "Error: Please enter a positive number of terms." << endl;
return 1;
}
double factorial = 1.0;
int i = 1;
do {
factorial *= i; // Calculate factorial for each term
e += 1.0 / factorial; // Add the term to the approximation
i++;
} while (i <= n);
cout << "Approximation of e with " << n << " terms: " << e << endl;
return 0;
}
Ex11: Write C++ program to find e from the following series: e = 1 + x + (x^2 / 2!) + (x^3 / 3!) + ... (x^a / a!) . using do-while loop.
Sol//
#include <iostream>
#include <cmath> // for std::factorial
using namespace std;
int main() {
double x, e = 1.0; // Initialize with 1
int a;
cout << "Enter the value of x: ";
cin >> x;
cout << "Enter the power a (positive integer): ";
cin >> a;
// Input validation (optional)
if (a <= 0) {
cout << "Error: Please enter a positive power a." << endl;
return 1;
}
double term = 1.0, power = x; // Initialize term and power
int i = 1;
do {
term *= power / i; // Calculate next term (x^i / i!)
e += term; // Add the term to the approximation
power *= x; // Update power for next term
i++;
} while (i <= a);
cout << "Approximation of e for x = " << x << " and a = " << a << " terms: " << e << endl;
return 0;
}
Ex 12: Write C++ program to print the following searies:
1. Sum=1+2^2 +4^2 + ... +n^2
2. Sum=1-3^x+5^x-... +n^x
3. Sum=1 + 1/1! +2/2!+3/3! + ... +n/n! where n!=1 *2*3* ... *n ..using do-while loop.
Sol//
#include <iostream>
#include <cmath> // for std::pow
using namespace std;
int main() {
int n;
double sum1 = 0, sum2 = 0, sum3 = 0;
double x; // for series 2
cout << "Enter the number of terms (n): ";
cin >> n;
// Input validation for n (positive integer)
if (n <= 0) {
cout << "Error: Please enter a positive number of terms." << endl;
return 1;
}
cout << "Enter the value of x for series 2 (optional, enter 0 for default 1): ";
cin >> x;
if (x == 0) {
x = 1; // Set default value for x
}
int i = 1;
double factorial = 1.0;
// Calculate and print the series using do-while loops
do {
sum1 += pow(i, 2); // Series 1: Sum of squares (1^2 + 2^2 + ... + n^2)
sum2 += pow(-1, i + 1) * pow(x, i); // Series 2: Alternating series (1 - 3x + 5x^2 - ...)
// Calculate factorial for series 3 within the loop for efficiency
factorial *= i;
sum3 += i / factorial; // Series 3: Sum of factorials (1 + 1/1! + 2/2! + ...)
i++;
} while (i <= n);
cout << "Series 1 (Sum of squares): " << sum1 << endl;
cout << "Series 2 (Alternating series): " << sum2 << endl;
cout << "Series 3 (Sum of factorials): " << sum3 << endl;
return 0;
}