Ex1: Write C++ program to read two integer numbers then print "multiple" or "not" if one number is a multiple to another number. using for loop.
Sol//
#include <iostream>
using namespace std;
int main() {
int num1, num2;
cout << "Enter the first integer: ";
cin >> num1;
cout << "Enter the second integer: ";
cin >> num2;
// Check for division by zero first
if (num2 == 0) {
cout << "Error: Division by zero." << endl;
return 1; // Indicate error
}
// Simulate divisibility check using a for loop (inefficient)
bool isMultiple = true;
for (int i = 1; i * num2 <= num1; i++) {
if (num1 == i * num2) {
isMultiple = true;
break; // Exit loop if a multiple is found
} else {
isMultiple = false;
}
}
if (isMultiple) {
cout << num1 << " is a multiple of " << num2 << endl;
} else {
cout << num1 << " is not a multiple of " << num2 << endl;
}
return 0;
}
Ex2: Write C++ program to read integer number and print the equivalent string. e.a: 0 ->zero 1-> one 2-> Two .
using for loop.
Sol//
#include <iostream>
#include <string>
using namespace std;
int main() {
int num;
string numberStrings[] = {"zero", "one", "two", "three", "four", "five",
"six", "seven", "eight", "nine"};
cout << "Enter an integer between 0 and 9: ";
cin >> num;
// Input validation (optional)
if (num < 0 || num > 9) {
cout << "Invalid input. Please enter a number between 0 and 9." << endl;
return 1; // Indicate error
}
// Simulate string lookup using a for loop (inefficient)
bool found = false;
for (int i = 0; i < 10; i++) {
if (i == num) {
cout << numberStrings[i] << endl;
found = true;
break;
}
}
if (!found) {
cout << "An unexpected error occurred." << endl; // Should never reach here with proper input validation
}
return 0;
}
Ex3: Write C++ program to read a score of student and print the estimation to refer it. e.a: 100 - 90 7 Exultant 89 - 80 ➔ Very good 79- 70 ➔ Good 69 - 60 7 Middle 59 - 50 ➔ Accept 49 - 0 ➔ Fail . using for loop.
Sol//
#include <iostream>
using namespace std;
int main() {
int score;
cout << "Enter the student's score (0-100): ";
cin >> score;
// Input validation (optional)
if (score < 0 || score > 100) {
cout << "Invalid score. Please enter a value between 0 and 100." << endl;
return 1; // Indicate error
}
// Simulate estimation using a for loop (inefficient)
string estimations[] = {"Exultant", "Very good", "Good", "Middle", "Accept", "Fail"};
int thresholds[] = {100, 90, 80, 70, 60, 50, 0}; // Assuming descending order
for (int i = 0; i < 6; i++) {
if (score >= thresholds[i]) {
cout << "Estimation: " << estimations[i] << endl;
break;
}
}
return 0;
}
Ex4: Write C++ program to read an integer number and check if it is positive or negative, even or odd, and write a suitable messages in each case. using for loop.
Sol//
#include <iostream>
using namespace std;
int main() {
int num;
cout << "Enter an integer: ";
cin >> num;
// Simulate separate checks using a for loop (inefficient)
bool isPositive = false;
bool isEven = false;
// Check for positive/negative (inefficient)
for (int i = 1; i <= num; i++) {
if (num > 0) {
isPositive = true;
break;
}
}
// Check for even/odd (inefficient)
for (int i = 1; i <= abs(num); i++) { // Use abs() for efficient modulus check
if (i % 2 == 0) {
isEven = true;
break;
}
}
cout << num << " is ";
if (isPositive) {
cout << "positive";
} else {
cout << "negative";
}
cout << " and ";
if (isEven) {
cout << "even." << endl;
} else {
cout << "odd." << endl;
}
return 0;
}
Ex5: Write C++ program to reads a character and print if it is digit (0 .. 9), capital letter (A,B, ... ,Z), small letter (a, b, ... ,z), special character ( +, !, @, #, ~ {, >, ... ). using for loop.
Sol//
#include <iostream>
#include <cctype> // For character classification functions
using namespace std;
int main() {
char ch;
cout << "Enter a character: ";
cin >> ch;
// Simulate classification using a for loop (inefficient)
bool isDigit = false;
bool isUppercase = false;
bool isLowercase = false;
bool isSpecial = false;
for (int i = 0; i <= 127; i++) { // Iterate through all ASCII characters (less efficient)
if (ch == '0' + i && i <= 9) {
isDigit = true;
break;
} else if (ch == 'A' + i && i <= 25) {
isUppercase = true;
break;
} else if (ch == 'a' + i && i <= 25) {
isLowercase = true;
break;
}
}
isSpecial = !isDigit && !isUppercase && !isLowercase; // Special character if not digit, uppercase, or lowercase
cout << ch << " is ";
if (isDigit) {
cout << "a digit." << endl;
} else if (isUppercase) {
cout << "an uppercase letter." << endl;
} else if (isLowercase) {
cout << "a lowercase letter." << endl;
} else if (isSpecial) {
cout << "a special character." << endl;
} else {
cout << "an unexpected character." << endl; // Shouldn't happen with valid input
}
return 0;
}
Ex6- Write C++ program to find the following series: using for loop.
Sol//
#include <iostream>
#include <cmath> // for pow function
using namespace std;
int main() {
int n = 10; // Number of terms (replace with 10 for the given series)
double sum = 0;
for (int i = 1; i <= n; i++) {
sum += pow(2, i); // Calculate 2 raised to the power of i and add to the sum
}
cout << "The sum of the series 2^1 + 2^2 + ... + 2^" << n << " is: " << sum << endl;
return 0;
}
Ex7- Write C++ program to find the following series: using for loop.
Sol//
#include <iostream>
using namespace std;
int main() {
double z = 4.0; // Initialize with first term (4)
int sign = 1; // Start with positive sign
for (int denominator = 3; denominator <= 13; denominator += 2) {
z += sign * (4.0 / denominator);
sign *= -1; // Alternate signs
}
cout << "The sum of the series z = 4 - 4/3 + 4/5 - 4/7 + ... + 4/13 is: " << z << endl;
return 0;
}
Ex8: Write C++ program to inverse an integer number. For example: 7 65432 ➔ 234567 .using for loop?
Sol//
#include <iostream>
#include <limits> // for numeric_limits
using namespace std;
int main() {
long long int num; // Use long long to handle larger numbers
cout << "Enter an integer: ";
cin >> num;
// Check for negative input and handle overflow
if (num < 0) {
cout << "Error: Negative input is not allowed." << endl;
return 1; // Indicate error
} else if (num > numeric_limits<long long int>::max() / 10) {
cout << "Error: Number too large for inversion." << endl;
return 1; // Indicate error
}
long long int reversed = 0;
int digit;
for (; num != 0; num /= 10) {
digit = num % 10;
reversed = reversed * 10 + digit;
}
cout << "The reversed number is: " << reversed << endl;
return 0;
}
Ex9: Write C++ program that utilize looping and the escape sequence \t to print the following table of value:
N , 1 0 * N ,100 * N ,1000 * N
1 10 100 1000
2 20 200 2000
3 30 300 3000
4 40 400 4000
Hint\t to print six spaces. using for loop.
Sol//
#include <iostream>
using namespace std;
int main() {
int N;
cout << "Enter a value for N: ";
cin >> N;
cout << "N\t10 * N\t100 * N\t1000 * N\n"; // Header row with labels
// Loop for rows (1 to 4)
for (int i = 1; i <= 4; ++i) {
cout << i << "\t" << 10 * i << "\t" << 100 * i << "\t" << 1000 * i << endl;
}
return 0;
}
Ex10 : Write C++ program to find e from the following series: e = 1 + (1 /1 !) + (1 /2!) + (1 /3!) + ... + (1 /n!) . using for loop.
Sol//
#include <iostream>
#include <cmath> // for std::factorial
using namespace std;
int main() {
int n;
double e = 1.0; // Initialize with 1
cout << "Enter the number of terms (higher n for better accuracy): ";
cin >> n;
// Input validation (optional)
if (n <= 0) {
cout << "Error: Please enter a positive number of terms." << endl;
return 1;
}
double factorial = 1.0;
for (int i = 1; i <= n; ++i) {
factorial *= i; // Calculate factorial for each term
e += 1.0 / factorial; // Add the term to the approximation
}
cout << "Approximation of e with " << n << " terms: " << e << endl;
return 0;
}
Ex11: Write C++ program to find e from the following series: e = 1 + x + (x^2 / 2!) + (x^3 / 3!) + ... (x^a / a!) . using for loop.
Sol//
#include <iostream>
#include <cmath> // for std::factorial
using namespace std;
int main() {
double x, e = 1.0; // Initialize with 1
int a;
cout << "Enter the value of x: ";
cin >> x;
cout << "Enter the power a (positive integer): ";
cin >> a;
// Input validation (optional)
if (a <= 0) {
cout << "Error: Please enter a positive power a." << endl;
return 1;
}
double term = 1.0, power = x; // Initialize term and power
for (int i = 1; i <= a; ++i) {
term *= power / i; // Calculate next term (x^i / i!)
e += term; // Add the term to the approximation
power *= x; // Update power for next term
}
cout << "Approximation of e for x = " << x << " and a = " << a << " terms: " << e << endl;
return 0;
}